SOLUTION: A CARPENTER SAWS A BOARD INTO TWO PIECES. HE WANTS ONE PIECE TO BE ONE FOOT LONGER THAN TWICE THE LENGTH OF THE SHORTER PIECE. FIND THE LENGTH OF EACH PIECE. THE BOARDS 22 FEET.

Algebra ->  Points-lines-and-rays -> SOLUTION: A CARPENTER SAWS A BOARD INTO TWO PIECES. HE WANTS ONE PIECE TO BE ONE FOOT LONGER THAN TWICE THE LENGTH OF THE SHORTER PIECE. FIND THE LENGTH OF EACH PIECE. THE BOARDS 22 FEET.      Log On


   



Question 261068: A CARPENTER SAWS A BOARD INTO TWO PIECES. HE WANTS ONE PIECE TO BE ONE FOOT LONGER THAN TWICE THE LENGTH OF THE SHORTER PIECE. FIND THE LENGTH OF EACH PIECE. THE BOARDS 22 FEET.
Answer by rfer(16322) About Me  (Show Source):
You can put this solution on YOUR website!
x+2x+1=22
3x+1=22
3x=21
x=7 ft
2x+1=15 ft