SOLUTION: The endpint of the daimeter of a circle are at (-4,10) and (-8,0). What are the coordinates of ht ecenter of the circle?

Algebra ->  Circles -> SOLUTION: The endpint of the daimeter of a circle are at (-4,10) and (-8,0). What are the coordinates of ht ecenter of the circle?      Log On


   

Question 25670: The endpint of the daimeter of a circle are at (-4,10) and (-8,0). What are the coordinates of ht ecenter of the circle?
Found 2 solutions by rapaljer, askmemath:
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
The center is at the midpoint of the diameter. This is like the average of the x coordinates, and the average of the y coordinates. So, add the x coordinates and divide by 2, add the y coordinates and divide by 2.
x+=+%28%28-4%29+%2B+%28-8%29%29%2F2=+-12%2F2=+-6
y+=+%2810%2B0%29%2F2=+5

Coordinates of the center : (-6,5)

R^2 at SCC

Answer by askmemath(368) About Me  (Show Source):
You can put this solution on YOUR website!
The center of the circle is the mid-point of the two points
Therefore (-4+(-8)/2,(10+0)/2)
(-4-8/2,5)
(-12/2,5)
(-6,5)