SOLUTION: The measure of an angle is 10 less than 3 times the measure of its complement. Find the measure of both angles.
I'm doing:
x+y=90
x=3y-10
3y-10+y=90
4y-10=90
4y=80
y=20
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-> SOLUTION: The measure of an angle is 10 less than 3 times the measure of its complement. Find the measure of both angles.
I'm doing:
x+y=90
x=3y-10
3y-10+y=90
4y-10=90
4y=80
y=20
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Question 231629: The measure of an angle is 10 less than 3 times the measure of its complement. Find the measure of both angles.
I'm doing:
x+y=90
x=3y-10
3y-10+y=90
4y-10=90
4y=80
y=20
x=3y-10
x=3(20)-10
x=60-10
x=50
It doesn't equal 90! Help! Answer by solver91311(24713) (Show Source):
