SOLUTION: write the equation of the circle in radius-center form with the center at (2,1) and tangent to the line x=5.

Algebra ->  Circles -> SOLUTION: write the equation of the circle in radius-center form with the center at (2,1) and tangent to the line x=5.      Log On


   



Question 222182: write the equation of the circle in radius-center form with the center at (2,1) and tangent to the line x=5.
Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
write the equation of the circle in radius-center form with the center at (2,1) and tangent to the line x=5.

The equation of a circle in radius-center form is

%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2

where the center is the point %22%28h%2Ck%29%22 and
the radius is r.

So the equation, all but r, is:

%28x-2%29%5E2%2B%28y-1%29%5E2=r%5E2

So to find the radius r let's plot the center
%22%282%2C1%29%22

 


Now let's draw the line x=5, which is a vertical
line through 5 on the x-axis:

 





Now let's sketch in a circle tangent to that line:

 

Draw a radius from the center (2,1) over to the line.



Using the x-axis as a measuring stick, you can see that
that radius is 3 units long, so

r=3

and the final answer is

%28x-2%29%5E2%2B%28y-1%29%5E2=3%5E2  or

%28x-2%29%5E2%2B%28y-1%29%5E2=9

Edwin