SOLUTION: how do i find the perimeter of the triangle with vertices at three points (0,1),(2,1), and (0,3)? I know that P= a+b+c, so will thenext step be the sq root (X1-X2)+(Y1-Y2)+(Z1-Z

Algebra ->  Points-lines-and-rays -> SOLUTION: how do i find the perimeter of the triangle with vertices at three points (0,1),(2,1), and (0,3)? I know that P= a+b+c, so will thenext step be the sq root (X1-X2)+(Y1-Y2)+(Z1-Z      Log On


   



Question 212942: how do i find the perimeter of the triangle with vertices at three points (0,1),(2,1), and (0,3)?
I know that P= a+b+c, so will thenext step be the sq root (X1-X2)+(Y1-Y2)+(Z1-Z2)?

Answer by rfer(16322) About Me  (Show Source):
You can put this solution on YOUR website!
If you graph the points you will find a right triangle with two side measuring 2 each
c^2=b6^2+b^2
c^2=2^2+2^2
c=2.8
P=2+2+2.8
p=6.8