SOLUTION: A circle has center (p,q) and is tangent to the x-axis. Write the standard equation of the circle.
I got (x-p)^2 + (y-q)^2 = r^2 but I'm not sure about the radius. Please help
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-> SOLUTION: A circle has center (p,q) and is tangent to the x-axis. Write the standard equation of the circle.
I got (x-p)^2 + (y-q)^2 = r^2 but I'm not sure about the radius. Please help
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Question 194700: A circle has center (p,q) and is tangent to the x-axis. Write the standard equation of the circle.
I got (x-p)^2 + (y-q)^2 = r^2 but I'm not sure about the radius. Please help to clarify what I would do with r (radius) and why. Answer by scott8148(6628) (Show Source):
You can put this solution on YOUR website! the circle is tangent to the x-axis
this means that the distance (in the y direction) from the center to the x-axis is the radius
so the y-coordinate of the center (q) is the radius of the circle
