Question 164935This question is from textbook Geomertry
: Write an equation for the line parrallel to XY that contains point Z.
XY: x=1/2y + 1, Z(1,-2) This question is from textbook Geomertry
You can put this solution on YOUR website! ok, the first thing that you need to do is get the formula in slope-intercept form. where (x,y) is a coordinate; m=slope; b=the y-intercept
Given: x=1/2y+1
x-1=1/2y subtract 1 from both sides
2(x-1)=y multiply both sides by 2
or y=2(x-1) Identity
y=2x-2 distribute the 2
y=mx+b
now it is in slope-intercept form
so now we know that the slope of the original line is 2 and the y-intercept of the original line is -2
a line that is parallel to this one is going to have the same slope as this line. so the new line will be y=2x+b
We know that the line must go through the points (1,-2)
so plug these points in and solve for b
y =2 x +b
(-2)=2(1)+b plug in points x=1 y=-2
-2 =2+b simplify
-4=b subtract 2 from each side
now plug in the slope(m) and the y-intercept(b) of the new line into the slope intercept form and you get:
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