SOLUTION: how do you find the perimeter and area of a square whose side is y-3?

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Question 155739: how do you find the perimeter and area of a square whose side is y-3?

Found 2 solutions by ankor@dixie-net.com, jim_thompson5910:
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
P = 4(y-3)
P = 4y - 12
:
A = (y-3)^2
FOIL
A = y^2 - 6y + 9

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Perimeter of a Square: P=4s where "P" is the perimeter and "s" is the side length


P=4s Start with the general formula for the perimeter of a square


P=4%28y-3%29 Plug in the given side length of s=y-3


P=4y-12 Distribute


So the perimeter is P=4y-12





Area of a Square: A=s%5E2 where "A" is the area and "s" is the side length


A=s%5E2 Start with the general formula for the area of a square


A=%28y-3%29%5E2 Plug in the given side length of s=y-3


A=y%5E2-3y-3y%2B9 FOIL


A=y%5E2-6y%2B9 Combine like terms.


So the area is A=y%5E2-6y%2B9