SOLUTION: The center of circle P is at (8,6) and (13, 6 - sqrt39) is a point on the circle. If circle P is inscribed in square ABCD, what is the area of ABCD?
Algebra ->
Circles
-> SOLUTION: The center of circle P is at (8,6) and (13, 6 - sqrt39) is a point on the circle. If circle P is inscribed in square ABCD, what is the area of ABCD?
Log On
Question 143914: The center of circle P is at (8,6) and (13, 6 - sqrt39) is a point on the circle. If circle P is inscribed in square ABCD, what is the area of ABCD? Answer by solver91311(24713) (Show Source):
You can put this solution on YOUR website! Given the center of a circle and a point on the circle, you can use the distance formula to calculate the radius. The diameter of a circle inscribed in a square is equal to the side length of the square. So, take the radius that you calculated, double it, and then square the result for the area of the square.
