SOLUTION: write the equasion of a circle with a diameter having endpoints at (-2,6) and (8,4)?
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Question 142451
:
write the equasion of a circle with a diameter having endpoints at
(-2,6) and (8,4)?
Answer by
scott8148(6628)
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the center is midway between the endpoints at (3,5)
the radius squared is the square of the distance from the center to an endpoint
__ r^2=5^2+1^1
(x-3)^2+(y-5)^2=26