SOLUTION: What is the center and the radius of a circle with equation (x+1)^2+(y+3)^2=9/4?

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Question 140985: What is the center and the radius of a circle with equation (x+1)^2+(y+3)^2=9/4?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
center and the radius of a circle with equation (x+1)^2+(y+3)^2=9/4?
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center at (-1,-3); radius = sqrt(9/4) = 3/2
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Cheers,
Stan H.