SOLUTION: Given the endpoints of a diameter of a circle are S(0,5a) and T(2a,0), what is the radius of the circlr? I think it is (sqrt29/2)a . Can someone PLEASE help me ????

Algebra ->  Circles -> SOLUTION: Given the endpoints of a diameter of a circle are S(0,5a) and T(2a,0), what is the radius of the circlr? I think it is (sqrt29/2)a . Can someone PLEASE help me ????      Log On


   

Question 139721: Given the endpoints of a diameter of a circle are S(0,5a) and T(2a,0), what is the radius of the circlr? I think it is (sqrt29/2)a . Can someone PLEASE help me ????
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
You are correct!
Using: d+=+sqrt%28%28x%5B2%5D-x%5B1%5D%29%5E2%2B%28y%5B2%5D-y%5B1%5D%29%5E2%29 to find the diameter:
Substitute: (0, 5a) and (2a, 0)
d+=+sqrt%28%282a-0%29%5E2%2B%280-5a%29%5E2%29
d+=+sqrt%28%282a%29%5E2%2B%28%28-5a%29%5E2%29%29
d+=+sqrt%284a%5E2%2B25a%5E2%29
d+=+sqrt%2829a%5E2%29
d+=+a%2Asqrt%2829%29
The radius is just half the diameter, so...
r+=+a%2A%28sqrt%2829%29%2F2%29 which is precisely what you got!