SOLUTION: On a coordinate plane P(0,4a) and Q(3a,0) are the endpoints of a diameter of a circle. What is the radius of the circle?

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Question 134976: On a coordinate plane P(0,4a) and Q(3a,0) are the endpoints of a diameter of a circle. What is the radius of the circle?
Found 2 solutions by stanbon, vleith:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
On a coordinate plane P(0,4a) and Q(3a,0) are the endpoints of a diameter of a circle. What is the radius of the circle?
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Formula: distance = sqrt[(x-change)^2 + (y-change)^2]
d = sqrt[(3a)^2 + (4a)^2]
d = sqrt[25a^2]
d = 5a
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Cheers,
Stan H.

Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
You are given two points. The distance between two points is given as:
distance+=+sqrt%28%28x2+-+x1%29%5E2+%2B+%28y2+-+y1%29%5E2%29
distance+=+sqrt%28%283a+-+0%29%5E2+%2B+%280+-+4a%29%5E2%29
distance+=+sqrt%28%283a%29%5E2+%2B+%28-4a%29%5E2%29
distance+=+sqrt%289a%5E2+%2B+16a%5E2%29
distance+=+sqrt%2825a%5E2%29
distance = 5a