SOLUTION: I need help with truth tables. See question below. The symbol -> is an arrow for if...then. Construct a truth table for (~q^p)->~q

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Question 124049: I need help with truth tables. See question below. The symbol -> is an arrow for if...then.
Construct a truth table for (~q^p)->~q
Found 2 solutions by stanbon, chitra:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
This will probably get all jumbled up by the time you see it:

Construct a truth table for
(~ q ^ p) -> ~ q
.0..1..0..1...1...0..1
.0..1..0..0...1...0..1
.1..0..1..1...1...1..0
.1..0..0..0...1...1..0
=============================
Cheers,
Stan H.

Answer by chitra(359) About Me  (Show Source):
You can put this solution on YOUR website!
THE TRUTH TABLE FOR THE GIVEN COMPUND PROPOSITION IS AS FOLLOWS:

p Q ~Q (~Q ^ P) (~Q ^ P) --> ~Q
T T F F T
T F T T T
F T F F T
F F T F T

OR THIS CAN ALSO BE WRITEN IN THE FORM OF 0'S ADN 1'S
THAT IS REPLACE T BY 1 AND F BY 0

THUS WE FIND THAT THE GIVEN PROPOSITION IS A TAUTOLOGY

REVERT TO ME IF YOU STIL HAVE MANY DOUBTS ABOUT THE DISCRETE MATH

REGS