|
Question 121952This question is from textbook Glencoe Mathematics Geometry
: Find the value of x so that the line containing points at (x,2) and (-4, 5) is perpendicular to the line containing points at (4,8) and (2,-1).
I have determined that the slope for the line containing (4,8) and 2,-1 is 9/2 and thus the slope for the perpendicular line would be -2/9. I figured that if I used the y2-y1 over x2-x1 and set that = to -2/9 that I would get the answer and it just is not working. The book says that the answer is 9.5. Can you help?
This question is from textbook Glencoe Mathematics Geometry
Found 2 solutions by stanbon, solver91311:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Find the value of x so that the line containing points at (x,2) and (-4, 5) is perpendicular to the line containing points at (4,8) and (2,-1).
------------
Yes the slope is -2/9
----------------
EQUATION to solve for "x":
(2-5)/(x--4) = -2/9
Cross-multiply:
-2(x+4) = -27
x+4 = 13.5
x = 9.5 or 19/2
=====================
Cheers,
Stan H.
Answer by solver91311(24713)  (Show Source):
|
|
|
| |
