Question 1203796: Y is the center of the circle.
Arc CD = 30°
Arc AB = Arc AE
Arc ED = 120°
YC is perpendicular to BD
AB = 10cm
BG = 4cm
GC = 2cm
Solve for AE, YC and CD
Found 2 solutions by Edwin McCravy, greenestamps:
Answer by Edwin McCravy(20063)   (Show Source):
You can put this solution on YOUR website!
This problem is botched. The figure below is drawn to scale.
As you can look and readily see, if GC=2 cm, BG must be a lot longer than 4 cm.
In fact, BG would have to be 7.4641015 cm. So there is no use trying to
get an answer to this problem. If you give me corrected numbers, I'll help you.
Edwin
Answer by greenestamps(13206)  (Show Source):
You can put this solution on YOUR website!
The given information is inconsistent.
With BG=4 and YC perpendicular to BD, DG is also 4; arc CD equal to 30 degrees means the radius of the circle is 8.
Also with arc CD equal to 30 degrees and YC perpendicular to BD, arc BC is also 30 degrees, which makes EB a diameter of the circle. Then with arcs AB and AE having the same measure, each of them is 90 degrees, which makes AYB an isosceles right triangle. Then AB=10 means the radius of the circle is 5*sqrt(2), contradicting the information that it is 8.
Correct the given information and re-post the problem.
|
|
|
