SOLUTION: What is the correct standard equation of a circle with center (-4, 0) and radius 9? (x + 4)2 + y2 = 81 (x - 4)2 + y2 = 9 (x + 4)2 + y2 = 3 (x - 4)2 + y2 = 3 (x + 4)2 + y2 =

Algebra ->  Circles -> SOLUTION: What is the correct standard equation of a circle with center (-4, 0) and radius 9? (x + 4)2 + y2 = 81 (x - 4)2 + y2 = 9 (x + 4)2 + y2 = 3 (x - 4)2 + y2 = 3 (x + 4)2 + y2 =       Log On


   

Question 1194119: What is the correct standard equation of a circle with center (-4, 0) and radius 9?
(x + 4)2 + y2 = 81
(x - 4)2 + y2 = 9
(x + 4)2 + y2 = 3
(x - 4)2 + y2 = 3
(x + 4)2 + y2 = 9
(x - 4)2 + y2 = 81
Found 2 solutions by MathLover1, Alan3354:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
standard equation of a circle is:
%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2 where h and k are coordinates of a center, r is a radius

if center is at (-4, 0), means h=-4 and k=0
and radius r=9
then we have
%28x-%28-4%29%29%5E2%2B%28y-0%29%5E2=9%5E2
%28x%2B4%29%5E2%2By%5E2=81 => your answer





Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
What is the correct standard equation of a circle with center (-4, 0) and radius 9?
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%28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2 is a circle with its center at (h,k) and radius r.