SOLUTION: find how the circle x²+y²=1 and x²+y²-6x+5=0 touch each other and find the coordinate of the point of contact

Algebra ->  Circles -> SOLUTION: find how the circle x²+y²=1 and x²+y²-6x+5=0 touch each other and find the coordinate of the point of contact       Log On


   

Question 1182467: find how the circle x²+y²=1 and x²+y²-6x+5=0 touch each other and find the coordinate of the point of contact
Answer by MathLover1(20855) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2%2By%5E2=1+
x%5E2%2By%5E2-6x%2B5=0+
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x%5E2%2By%5E2-1+=0
x%5E2%2By%5E2-6x%2B5=0
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the point of contact will be where
x%5E2%2By%5E2-1+=x%5E2%2By%5E2-6x%2B5.........simplify
cross%28x%5E2%29%2Bcross%28y%5E2%29-1+=cross%28x%5E2%29%2Bcross%28y%5E2%29-6x%2B5
-1+=-6x%2B5
6x+=1%2B5
6x+=6
x=1
go to
x%5E2%2By%5E2=1 ....substitute x
1%5E2%2By%5E2=1
1%2By%5E2=1+
y%5E2=1-1
y%5E2=0
y=0
the point of contact will be at (1,0)