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Question 1174624: Find the equation of the line that is parallel to the given line and passes through (5, -1) y = 2x−7
Found 2 solutions by math_helper, mccravyedwin:
Answer by math_helper(2461)   (Show Source):
You can put this solution on YOUR website!
y = mx + b is the slope-intercept form of a line
m is the slope (the amount of rise divided by the amount of run, also known as (change in y) / (change in x))
b is the y-intercept (where the line crosses the y-axis, i.e. the y value you get when x=0)
Parallel lines have equal slope.
Using the point-slope form, y-y0 = m(x-x0) with m=2, (x0,y0) = (5,-1):
y - (-1) = 2(x - 5) << point-slope form of the parallel line
y + 1 = 2x - 10
y = 2x - 11 << slope-intercept form of the parallel line
Answer by mccravyedwin(407)  (Show Source):
You can put this solution on YOUR website!
Equations of parallel lines need differ only by their constant term(s).
y = 2x-7 has only the constant term -7. Substitute any letter for the constant
term, say b.
y = 2x+b
Now all we need do is substitute the point (5,-1) in it
-1 = 2(5)+b
-1 = 10+b
-11 = b
Substitute 11 for b in
y = 2x+b and get
y = 2x-11 <--answer
Edwin
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