SOLUTION: Find the equation of the line perpendicular to 2x+3y=1 and whose distance from the origin is 7. Please include solutions if you can. Thank you!
Algebra ->
Points-lines-and-rays
-> SOLUTION: Find the equation of the line perpendicular to 2x+3y=1 and whose distance from the origin is 7. Please include solutions if you can. Thank you!
Log On
Question 1172331: Find the equation of the line perpendicular to 2x+3y=1 and whose distance from the origin is 7. Please include solutions if you can. Thank you!
The left side of an equation of a line PARALLEL to a given line Ax+By=C has
the same left side Ax+By but a different number for C on the right.
The left side of an equation of a line PERPENDICULAR to a given line Ax+By=C
has the left side Bx-Ay but a different number for C on the right.
So a line perpendicular to 2x+3y=1 has left side 3x-2y. Let's say it's right
side is a number C.
Then we use the formula
Distance from the point (x1,y1)
to the line Ax+By+C=0 is
d =
So there are two solutions:
The given line is:
Here is the first line in red.
The green line to the origin is 7 units long:
Here is the second line , also in red.
The green line to the origin is also 7 units long:
Edwin