SOLUTION: Two semicircular areas, adjacent to a rectangular area in the school gym, are to be painted. If the length of the rectangular area is 40 m and its perimeter is 120 m, what is the t

Algebra ->  Circles -> SOLUTION: Two semicircular areas, adjacent to a rectangular area in the school gym, are to be painted. If the length of the rectangular area is 40 m and its perimeter is 120 m, what is the t      Log On


   



Question 1169593: Two semicircular areas, adjacent to a rectangular area in the school gym, are to be painted. If the length of the rectangular area is 40 m and its perimeter is 120 m, what is the total painted area?

Answer by ikleyn(52792) About Me  (Show Source):
You can put this solution on YOUR website!
.

Two semicircle areas together comprise the entire circle,


and its diameter is equal to the width of the gym, i.e.

     %28120-2%2A40%29%2F2 = %28120-80%29%2F2 = 40%2F2 = 20 meters.


So, all you need is to find the area of a circle having the radius of 10 meters.


It is  100pi square meters.    ANSWER

Solved and explained in all details.