SOLUTION: Which is the equation of a circle that passes through (2.2) and is centered at (5.6) Answers: A. (x-6)^2 + (y-5)^2=25 B. (x-5)^2 + (y-6)^2=5 C. (x+5)^2 + (y+6)^2=25 D. (x-5)

Algebra ->  Circles -> SOLUTION: Which is the equation of a circle that passes through (2.2) and is centered at (5.6) Answers: A. (x-6)^2 + (y-5)^2=25 B. (x-5)^2 + (y-6)^2=5 C. (x+5)^2 + (y+6)^2=25 D. (x-5)      Log On


   

Question 1159152: Which is the equation of a circle that passes through (2.2) and is centered at (5.6)
Answers:
A. (x-6)^2 + (y-5)^2=25
B. (x-5)^2 + (y-6)^2=5
C. (x+5)^2 + (y+6)^2=25
D. (x-5)^2 + (y-6)^2=25
Thank you for doing this during quarantine :)
Found 3 solutions by Alan3354, MathLover1, MathTherapy:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Which is the equation of a circle that passes through (2.2) and is centered at (5.6)
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Use commas for the points.
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Which is the equation of a circle that passes through (2,2) and is centered at (5,6)
Find the distance between the 2 points.
That's the radius of the circle.
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%28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2 is a circle, where (h,k) is the center.

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

Which is the equation of a circle that passes through (2,2) and is centered at (5,6)

recall: the equation of a circle is %28x-h%29%5E2+%2B+%28y-k%29%5E2=r%5E2 where h and k are coordinates of the center and r is radius

Answers:
A. %28x-6%29%5E2+%2B+%28y-5%29%5E2=25=>h=6, k=5 -> not your answer
B. %28x-5%29%5E2+%2B+%28y-6%29%5E2=5=>h=5, k=5 -> might be your answer
check if this a circle that passes through (2,2)
%282-5%29%5E2+%2B+%282-6%29%5E2=5
3%5E2+%2B+%28-4%29%5E2=5
9+%2B+16=5
25%3C%3E5=> a circle does not passes through (2,2)
so, B. is not your answer either

C. %28x%2B5%29%5E2+%2B+%28y%2B6%29%5E2=25=>h=-5, k=-6 -> not your answer

D. %28x-5%29%5E2+%2B+%28y-6%29%5E2=25=>h=5, k=6 -> might be your answer
check if this a circle that passes through (2,2)
%282-5%29%5E2+%2B+%282-6%29%5E2=25
3%5E2+%2B+%28-4%29%5E2=25
9+%2B+16=25
25=25=> true=>this is a circle that passes through (2,2)
and have a center at (5,6)
so, your answer is D.

Answer by MathTherapy(10553) About Me  (Show Source):
You can put this solution on YOUR website!
Which is the equation of a circle that passes through (2.2) and is centered at (5.6)
Answers:
A. (x-6)^2 + (y-5)^2=25
B. (x-5)^2 + (y-6)^2=5
C. (x+5)^2 + (y+6)^2=25
D. (x-5)^2 + (y-6)^2=25
Thank you for doing this during quarantine :)
DON'T do it the way she tells you to! 

And, the points are: (2, 2) and (5, 6)

Equation of a circle: matrix%281%2C3%2C+%28x+-+h%29%5E2+%2B+%28y+-+k%29%5E2%2C+%22=%22%2C+r%5E2%29, where: (h, k) are the coordinates of the center

                                                     (x, y) is a point on the circumference

                                                     r is the radius

We then get: matrix%281%2C3%2C+%282+-+5%29%5E2+%2B+%282+-+6%29%5E2%2C+%22=%22%2C+r%5E2%29 ------ Substituting (2, 2) for (x, y), and (5, 6) for (h, k)

             matrix%282%2C3%2C+9+%2B+16%2C+%22=%22%2C+r%5E2%2C+25%2C+%22=%22%2C+r%5E2%29

              ----- Substituting (5, 6) for (h, k), and 25 for r2