SOLUTION: What is the general form of the equation of a circle with its center at (-2, 1) and passing through (-4, 1)? A. x2 + y2 − 4x + 2y + 1 = 0 B. x2 + y2 + 4x − 2y + 1 =

Algebra ->  Circles -> SOLUTION: What is the general form of the equation of a circle with its center at (-2, 1) and passing through (-4, 1)? A. x2 + y2 − 4x + 2y + 1 = 0 B. x2 + y2 + 4x − 2y + 1 =       Log On


   

Question 1154859: What is the general form of the equation of a circle with its center at (-2, 1) and passing through (-4, 1)?
A.
x2 + y2 − 4x + 2y + 1 = 0
B.
x2 + y2 + 4x − 2y + 1 = 0
C.
x2 + y2 + 4x − 2y + 9 = 0
D.
x2 − y2 + 2x + y + 1 = 0

Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
The given center and the given point indicate a radius of 2.

Starting with %28x%2B2%29%5E2%2B%28y-1%29%5E2=2%5E2

x%5E2%2B4x%2B4%2By%5E2-2y%2B1=4
x%5E2%2B4x%2By%5E2-2y%2B5-4=0
x%5E2%2B4x%2By%5E2-2y%2B1=0