SOLUTION: The radius of the circle is 17 m. The radius
CD is perpendicular to the chord AB. Their
point of intersection, E, is 8 m from the
center C. What is the length of the chord
AB?
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-> SOLUTION: The radius of the circle is 17 m. The radius
CD is perpendicular to the chord AB. Their
point of intersection, E, is 8 m from the
center C. What is the length of the chord
AB?
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Question 1153751: The radius of the circle is 17 m. The radius
CD is perpendicular to the chord AB. Their
point of intersection, E, is 8 m from the
center C. What is the length of the chord
AB? Found 3 solutions by ikleyn, greenestamps, MathLover1:Answer by ikleyn(52786) (Show Source):
Make a sketch and apply the Pythagorean theorem to right angled triangle CDA
the length of AD = = = = 15.
Hence, the length of AB is twice this length, i.e. AB = 2*15 = 30 meters. ANSWER
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I think that EVERYBODY and EVERYONE is able to solve it on his or her own, under one indispensable condition:
he or she should make his or her first step producing a sketch.
Draw the radius CA; that forms right triangle CEA in which the lengths of the hypotenuse and one leg are known. Use the Pythagorean Theorem to find the length of the other leg.
That other leg is half the length of the chord, so double the length of that leg to find the length of the chord.