SOLUTION: Place point C on the graph such that the directed line segment AB is partitioned using the ratio of 1 to 3. Where would point c be?

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Question 1150948: Place point C on the graph such that the directed line segment AB is partitioned using the ratio of 1 to 3.
Where would point c be?
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

Let C be the point that divides AB+ in the ratio 1%3A3.
A=(x%5B1%5D,y%5B1%5D)=(-4,4),
B=(x%5B2%5D,y%5B2%5D)=(6,-5) and
a%3Ab=1%3A3=>a=1, b=3

C=(%28bx%5B1%5D%2Bax%5B2%5D%29%2F%28a%2Bb%29,%28by%5B1%5D%2Bay%5B2%5D%29%2F%28a%2Bb%29)
C=(%283%2A%28-4%29%2B1%2A6%29%2F%281%2B3%29,%283%2A4%2B1%2A%28-5%29%29%2F%281%2B3%29)
C=(%28-12%2B6%29%2F4,%2812-5%29%2F4)
C=(-6%2F4,7%2F4)
C=(-3%2F2,7%2F4)
Here,




Therefore, the point C(-3%2F2,7%2F4) divides AB in the ratio 1%3A3.