SOLUTION: Find the shortest distance from the origin to the graph of the circle with equation given below. x^2−12x+y^2−12y+36=0

Algebra ->  Circles -> SOLUTION: Find the shortest distance from the origin to the graph of the circle with equation given below. x^2−12x+y^2−12y+36=0      Log On


   



Question 1145650: Find the shortest distance from the origin to the graph of the circle with equation given below.

x^2−12x+y^2−12y+36=0

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Find the shortest distance from the origin to the graph of the circle with equation given below.

x^2−12x+y^2−12y+36=0
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Find the center of the circle and its radius.
x^2−12x+y^2−12y+36=0
x^2−12x+y^2−12y = -36
(x-6)^2 + (y-6)^2 = -36 + 36 + 36 = 36
The center is (6,6) and the radius is 6.
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Find the distance d to the center.
d+=+sqrt%286%5E2+%2B+6%5E2%29+=+6sqrt%282%29
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Subtract the radius if d is > radius.
Distance = 6sqrt%282%29+-+6