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Question 1145401: Find the distance between the pair of parallel lines.
y = 2x + 4
y = 2x - 4
Found 3 solutions by Cromlix, ikleyn, Alan3354: Answer by Cromlix(4381) (Show Source): Answer by ikleyn(52767) (Show Source):
You can put this solution on YOUR website! .
Actually, the distance between two parallel lines on a plane is the length of (any) perpendicular between these lines.
To find the distance in this case, take any point on one line and calculate its distance from the second line.
For simplicity, put x= 0 and from the first equation find y= 2*0 + 4 = 4.
Thus the point (0,4) lies on the first line.
To find the distance from this point (0,4) to the line y = 2x - 4, use the general formula
for the distance from the point (p,q) on the coordinate plane to the line Ax + BY + C = 0
d = .
In your case the point is (0,4) and the line is 2x - y - 4 = 0, so A= 2, B= -1, C= -4, p= 0 and q= 4,
and the formula (1) takes the form
d = = = = = 3.577 (approximately). ANSWER
Solved.
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On formula (1), see the lessons
- The distance from a point to a straight line in a coordinate plane
- HOW TO calculate the distance from a point to a straight line in a coordinate plane
- Using formula for the distance from a point to a straight line in a plane to solve word problems
in this site.
Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Find the distance between the pair of parallel lines.
y = 2x + 4
y = 2x - 4
==========
m = slope = 2
Difference between the y-intercepts = 8
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d =~ 3.5777
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