|
Question 1144213: The ordinate of a point P is twice the abscissa. The point is equidistant from (-3,1) and (8,2). Find the coordinates of P.
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! The ordinate of a point P is twice the abscissa. The point is equidistant from (-3,1) and (8,2). Find the coordinates of P.
-----------
The ordinate of a point P is twice the abscissa.
---> y = 2x
---------------------
The point is equidistant from (-3,1) and (8,2)
-----
Find the perpendicular bisector of the line thru the 2 points.
P is the intersection of that line and y = 2x
|
|
|
| |
