SOLUTION: The circle is tangent to the line 5x+y=3 at the point (4,-4) and center is on the line x-2y=19. Find the equation of the circle. (I'm struggling to find the center in x-2y=19 that

Algebra ->  Circles -> SOLUTION: The circle is tangent to the line 5x+y=3 at the point (4,-4) and center is on the line x-2y=19. Find the equation of the circle. (I'm struggling to find the center in x-2y=19 that       Log On


   

Question 1139515: The circle is tangent to the line 5x+y=3 at the point (4,-4) and center is on the line x-2y=19. Find the equation of the circle. (I'm struggling to find the center in x-2y=19 that says to be perpendicular to the center itself and to the point of tangency)
Found 2 solutions by Alan3354, ikleyn:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
The circle is tangent to the line 5x+y=3 at the point (4,-4) ...
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The point (4,-4) is not on the line, so the circle cannot be tangent at that point.

Answer by ikleyn(52832) About Me  (Show Source):
You can put this solution on YOUR website!
.

You missed  EVERYTHING  in your post: 

    1)  the point (4,-4) does not belong to the line 5x + y = 3.



    2)  the line x - 2y IS NOT perpendicular to the center

        (due to that simple reason that the line can not be perpendicular to a point . . . 

             - by the definition and by the rules of using of these terms).