SOLUTION: Find the length of the intercepts of the circle 3x^2+3y^2-5x+3y=0 on the co-ordinate axes.

Algebra ->  Circles -> SOLUTION: Find the length of the intercepts of the circle 3x^2+3y^2-5x+3y=0 on the co-ordinate axes.      Log On


   

Question 1132621: Find the length of the intercepts of the circle 3x^2+3y^2-5x+3y=0 on the co-ordinate axes.
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
The intercepts with the axes are easy to find.

The x-axis is the line y=0 , so we find the intercepts from
system%28y=0%2C3x%5E2%2B3y%5E2-5x%2B3y=0%29 --> system%28y=0%2C3x%5E2-5x=0%29 --> system%28y=0%2Cx%283x-5%29=0%29 --> system%28y=0%2C%22and%22%2Cx=0%2C%22or%22%2Cx=5%2F3%29 .
Those intercepts are the points O%280%2C0%29 and A%285%2F3%2C0%29 .
The distance between the two intercepts of the circle with the x-axis is
5%2F3-0=highlight%285%2F3%29 .

The y-axis is the line x=0 , so we find the intercepts from
system%28x=0%2C3x%5E2%2B3y%5E2-5x%2B3y=0%29 --> system%28x=0%2C3y%5E2%2B3y=0%29 --> system%28x=0%2C3y%28y%2B1%29=0%29 --> system%28x=0%2C%22and%22%2Cy=0%2C%22or%22%2Cy=-1%29 .
Those intercepts are the points O%280%2C0%29 and B%280%2C-1%29 .
The distance between the two intercepts of the circle with the x-axis is
0-%28-1%29=highlight%281%29 .