SOLUTION: find the equation of the set of points whose distance of each element from (3,2) is twice its distance from (-1,4). thanks youuu
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Question 1130575: find the equation of the set of points whose distance of each element from (3,2) is twice its distance from (-1,4). thanks youuu Found 2 solutions by josgarithmetic, ikleyn:Answer by josgarithmetic(39630) (Show Source):
You can put this solution on YOUR website! .
find the equation of the set of points whose distance of each element from (3,2) is twice its distance from (-1,4). thank youuu
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Let (x,y) is the point of the locus (of the set of points).
Its distance from the point (3,2) is .
Its distance from the point (-1,4) is = .
From the condition,
= .
Square both sides
(x-3)^2 + (y-2)^2 = 4*((x+1)^2 + (y-4)^2).
FOIL
x^2 - 6x + 9 + y^2 - 4y + 4 = 4x^2 + 8x + 4 + 4y^2 - 32y + 64
3x^2 + 14x + 3y^2 - 28y = -51
x^2 + + y^2 - = - 17
x^2 + + + y^2 - + = -17 + +
(x+14/6)^2 + (y-28/6)^2 = -17 + = -17 + = .
Answer. This locus (= this set of points) is the circle with the equation
+ = .
The circle is centered at (,) and has the radius of units.
Solved.
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Be aware : The equation which @josgarithmetic proposes you to simplify, is INCORRECT (!)