SOLUTION: Find the square. (7p+6q) squared

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Question 112856: Find the square.
(7p+6q) squared

Found 2 solutions by jim_thompson5910, bucky:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
%287p%2B6q%29%5E2 Start with the given expression

%287p%2B6q%29%287p%2B6q%29 Expand


Remember, when you FOIL an expression, you follow this procedure:


Multiply the First terms:%287p%29%2A%287p%29=49p%5E2


Multiply the Outer terms:%287p%29%2A%286q%29=42pq


Multiply the Inner terms:%286q%29%2A%287p%29=42qp


Multiply the Last terms:%286q%29%2A%286q%29=36q%5E2


49p%5E2%2B42pq%2B42qp%2B36q%5E2 Now collect every term to make a single expression



49p%5E2%2B84pq%2B36q%5E2 Now combine like terms





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Answer:
So %287p%2B6q%29%287p%2B6q%29 foils and simplifies to 49p%5E2%2B84pq%2B36q%5E2

In other words, %287p%2B6q%29%287p%2B6q%29=49p%5E2%2B84pq%2B36q%5E2

Notice how 49p%5E2%2B84pq%2B36q%5E2 factors back to the original expression %287p%2B6q%29%287p%2B6q%29 (if you need help with factoring, check out this solver). So this verifies our answer.

Answer by bucky(2189) About Me  (Show Source):
You can put this solution on YOUR website!
Given:
.
7p%2B6q%29%5E2
.
To expand this recognize that when you square a quantity you multiply it by itself.
Therefore, multiply %287p%2B6q%29 by itself. You can write this problem as:
.
%287p%2B6q%29%2A%287p%2B6q%29
.
To do this multiplication, you can first multiply the 7p in the first set of parentheses
by each of the terms in the second set of parentheses. In other words, multiply:
.
7p%2A%287p+%2B+6q%29 and you get 49p%5E2+%2B+42pq.
.
Next multiply the 6q in the first set of parentheses by each of the terms in the second
set of parentheses. In other words, this time multiply:
.
6q%2A%287p+%2B+6q%29 and you get 42pq+%2B+36q%5E2
.
Finally, add the two products and simplify. Adding the two products:
.
49p%5E2+%2B+42pq+%2B+42pq+%2B+36q%5E2
.
Notice that the two middle terms can be combined, and the resulting polynomial is:
.
49p%5E2+%2B+84pq+%2B36q%5E2
.
That's the answer to the problem. Hope this helps you to understand how to square a binomial
quantity.
.