SOLUTION: Which of these is the equation of a circle with center at the origin and radius 2√3?
1. x2 + y2 = 0
2. x2 + y2 – 12 = 0
3. x2 + y2 = 2√3
4. (x- 2)2 + (y- 3)2 =
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-> SOLUTION: Which of these is the equation of a circle with center at the origin and radius 2√3?
1. x2 + y2 = 0
2. x2 + y2 – 12 = 0
3. x2 + y2 = 2√3
4. (x- 2)2 + (y- 3)2 =
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Question 1116777: Which of these is the equation of a circle with center at the origin and radius 2√3?
1. x2 + y2 = 0
2. x2 + y2 – 12 = 0
3. x2 + y2 = 2√3
4. (x- 2)2 + (y- 3)2 = 12
What's the formula? Answer by rothauserc(4718) (Show Source):
You can put this solution on YOUR website! formula for a circle whose center is the origin is
:
x^2 + y^2 = r^2, where r is the radius of the circle
:
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answer is option 2 since (2 * square root(3))^2 = 12
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