SOLUTION: Find the equation of circle center at (1,3) and tangent to the line 5x-12y=8. please explain.

Algebra ->  Points-lines-and-rays -> SOLUTION: Find the equation of circle center at (1,3) and tangent to the line 5x-12y=8. please explain.      Log On


   

Question 1115770: Find the equation of circle center at (1,3) and tangent to the line 5x-12y=8. please explain.
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Find the equation of circle center at (1,3) and tangent to the line 5x-12y=8.
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You can find the equation of the line perpendicular to the given line thru the point.
then find the distance from the point to the line, that's the radius.
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Then %28x-1%29%5E2+%2B+%28y-3%29%5E2+=+r%5E2 is the circle.
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Or, use
5x-12y-8 = 0
a = 5, b = -12, c = -8
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r+=+ABS%28a%2Ax%5B0%5D+%2B+b%2Ay%5B0%5D+%2B+c%29%2Fsqrt%28a%5E2%2Bb%5E2%29 to find the distance.
%28x%5B0%5D+y%5B0%5D%29 is the point.