Question 1107104: A circle with centre (2,-3) has a tangent of 24x+7y-12=0. Find the equation of the circle
I have no idea how to do this question, please send help!
Found 2 solutions by Alan3354, Edwin McCravy:
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! A circle with centre (2,-3) has a tangent of 24x+7y-12=0. Find the equation of the circle
===================
Hint:
The radial from the center to the tangent line is perpendicular to the tangent line.
Answer by Edwin McCravy(20064)  (Show Source):
You can put this solution on YOUR website! A circle with centre (2,-3) has a tangent of 24x+7y-12=0. Find the equation of the circle.
Here's the graph:
You have the center. You need the radius, which is the green line.
What you need is the distance formula from a point to a line:
The perpendicular distance from the point (x1,y1)to the line
Ax+By+C=0 is
d = 
Your line is 24x+7y-12 = 0
So you plug in A=24, B=7, C=-12 and (x1,y1) = (2,-3)
Substitute that into the formula for d. That will be the radius r.
Then substitute (h,k) = (2,-3) and that value of r into
If you have any difficulty, tell me in the note form below and I'll
get back to you by email.
Edwin
|
|
|
