SOLUTION: The circle x^2+y^2-4x-6y=0 cuts the x-axis at A and y-axis at B. A line y=5 cuts the circle at P and Q. Find the coordinates of A and B, then find the coordinates of P and Q. Fina

Algebra ->  Circles -> SOLUTION: The circle x^2+y^2-4x-6y=0 cuts the x-axis at A and y-axis at B. A line y=5 cuts the circle at P and Q. Find the coordinates of A and B, then find the coordinates of P and Q. Fina      Log On


   



Question 1105833: The circle x^2+y^2-4x-6y=0 cuts the x-axis at A and y-axis at B. A line y=5 cuts the circle at P and Q. Find the coordinates of A and B, then find the coordinates of P and Q. Finally find ∠OQA
Thank you!

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2%2By%5E2-4x-6y=0
x%5E2-4x%2By%5E2-6y=0
Complete square:
x%5E2-4x%2B4%2By%5E2-6y%2B9=0%2B4%2B9
%28x-2%29%5E2%2B%28y-3%29%5E2=13
Circle has center O(2,3) and radius r=sqrt%2813%29



∠OQA looks like a right angle. That will be the case if
the slopes of OQ and OA are negative reciprocals.  So let's
find out if OQ and OA are perpendicular:

Slope of OQ:

m%22%22=%22%22%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29
where (x1,y1) = O(2,3)
and where (x2,y2) = (5,5)
m%22%22=%22%22%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29
m%22%22=%22%22%285-3%29%2F%285-2%29
m%22%22=%22%222%2F3

Slope of OA:

m%22%22=%22%22%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29
where (x1,y1) = O(2,3)
and where (x2,y2) = A(4,0)
m%22%22=%22%22%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29
m%22%22=%22%22%280-3%29%2F%284-2%29
m%22%22=%22%22-3%2F2

The slopes are negative reciprocals so ∠QQA = 90°

Edwin