Question 1104952: A tractor has a rear wheel with a circumference of x m. The circumference of the front wheel is 2 m less. If the front wheel makes 12 more revolutions than the rear wheel every 480 m, what is the circumference , in m, of the front wheel?
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! A tractor has a rear wheel with a circumference of x m.
The circumference of the front wheel is 2 m less.
If the front wheel makes 12 more revolutions than the rear wheel every 480 m, what is the circumference , in m, of the front wheel?
:
(x-2) = the front wheel circumference
:
front rev - rear rev = 12 rev
 -  = 12
multiply equation by x(x-2(, cancel the denominators
480x - 480(x-2) = 12x(x-2)
480x - 480x + 960 = 12x^2 - 24x
Combine to form a quadratic equation
12x^2 - 24x - 960 = 0
simplify, divide by 12
x^2 - 2x - 80 = 0
Factors to
(x-10)(x+8) = 0
The positive solution
x = 10 meters is the circumference of the rear wheel
"what is the circumference , in m, of the front wheel?"
8 meters is the circumference of th front wheel
:
;
Check
480/8 - 480/10 =
60 - 48 = 12
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