SOLUTION: 1. Find the possible values of the constant m, for
which the curve (m+5)x² + (m²- 1)y² +2x - 5y = 0
is a circle.
2. P(0, 2) and Q(4,0) are two points in a plane and
0 is the or
Algebra ->
Circles
-> SOLUTION: 1. Find the possible values of the constant m, for
which the curve (m+5)x² + (m²- 1)y² +2x - 5y = 0
is a circle.
2. P(0, 2) and Q(4,0) are two points in a plane and
0 is the or
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Question 1092242: 1. Find the possible values of the constant m, for
which the curve (m+5)x² + (m²- 1)y² +2x - 5y = 0
is a circle.
2. P(0, 2) and Q(4,0) are two points in a plane and
0 is the origin. Find the equation of the:
i) Circle on PQ as diameter
ii) diameter parallel to the tangent of the circle at Q
b) Show that the line 2y + 1 = 0 is a tangent to the
circle.
3. Find the equation of the circle whose centre is
on the x- axis and which passes through the
points (0,3) and (4,1)
4. The displacement of a particle is given by x= 5t
+ 6t³. Find the :
i) initial velocity
ii) the acceleration at t =2 Answer by ikleyn(52787) (Show Source):
