SOLUTION: The length of a rectangle is {{{ x/(x+1) }}} meters, while its width is {{{ 3/(x-1) }}} meters. Please find its perimeter. TY

Algebra ->  Points-lines-and-rays -> SOLUTION: The length of a rectangle is {{{ x/(x+1) }}} meters, while its width is {{{ 3/(x-1) }}} meters. Please find its perimeter. TY      Log On


   

Question 1087160: The length of a rectangle is +x%2F%28x%2B1%29+ meters, while its width is +3%2F%28x-1%29+ meters. Please find its perimeter. TY
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
The length of a rectangle is +x%2F%28x%2B1%29+ meters, while its width is +3%2F%28x-1%29+ meters. Please find its perimeter.
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P = 2L + 2W