|
Question 1085811: find the equation, in standard form, of the circle being described in each item.
1.diameter with endpoints (3,-5) & (6,4)
2.center (-6,-3), through (-10,3)
Answer by mathmate(429)   (Show Source):
You can put this solution on YOUR website! Question:
find the equation, in standard form, of the circle being described in each item.
1.diameter with endpoints (3,-5) & (6,4)
2.center (-6,-3), through (-10,3)
Solution:
Standard form of a circle is
(x-x0)^2+(y-y0)^2=r^2
1.
Diameter end points = (3,-5), (6,4)
Centre=((3+6)/2, (-5+4)/2))=(4.5,-0.5)
radius, r = (1/2)sqrt((6-3)^2+(4--5)^2)=(1/2)sqrt(9+81)=(1/2)sqrt(90)=(3/2)sqrt(10),
r²=(3/2)²(sqrt(10)²)=9/4*10=45/2
So standard form:
(x-4.5)²+(y+0.5)²=45/2
2. radius = sqrt((-10--6)²+(3--3)²)=sqrt(16+36)=sqrt(52)
r²=52
standard form:
(x--6)²+(y--3)²=52
=>
(x+6)²+(y+3)²=52
|
|
|
| |
