SOLUTION: Find the equation of the circle that passes through (-1,1) and with centre at the point of intersection of x + 3y + 7 = 0 and 3x - 2y - 12 = 0.
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-> SOLUTION: Find the equation of the circle that passes through (-1,1) and with centre at the point of intersection of x + 3y + 7 = 0 and 3x - 2y - 12 = 0.
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Question 1078546: Find the equation of the circle that passes through (-1,1) and with centre at the point of intersection of x + 3y + 7 = 0 and 3x - 2y - 12 = 0. Found 2 solutions by Fombitz, MathLover1:Answer by Fombitz(32388) (Show Source):
You can put this solution on YOUR website! Find the point of intersection.
Substitute into the second equation,
So,
So then,
Using the point,
Finally,
You can put this solution on YOUR website!
Find the equation of the circle that passes through (,) and with center at the point of intersection of and .
equation of the circle:
and are and coordinates of center, and is radius
use and to find and coordinates of center
...........solve for ............substitute in equation
find
so, and coordinates of center are: and
and equation of your circle (so far) is:
use given point (,) and substitute its and coordinates
->equation of your circle