SOLUTION: An ellipse and a hyperbola have the same foci, $A$ and $B$, and intersect at four points. The ellipse has major axis 50, and minor axis 40. The hyperbola has conjugate axis of leng

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Question 1074904: An ellipse and a hyperbola have the same foci, $A$ and $B$, and intersect at four points. The ellipse has major axis 50, and minor axis 40. The hyperbola has conjugate axis of length 20. Let $P$ be a point on both the hyperbola and ellipse. What is $PA \cdot PB$?
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
If P is a point in an ellipse with foci A and B, and major axis 50,
by the definition of ellipse,
PA+PB=50.
If the minor axis of that ellipse is 40,
them the semimajor and senior acrs are respectively
a=25 and b=20.
That makes the focal distance
c=15.

For a hyperbola, the focal distance,
the distance between the vertices (the transverse axis),
and the conjugate axis are related by
a%5E2%2Bb%5E2=c%5E2 , where c is the focal distance,
2b is the conjugate axis, and
2a is the transverse axis.
So for this hyperbola, 2b=20, so b=10,
and c=15, so
a=sqrt%2815%5E2-10%5E2%29=sqrt%28225-100%29=sqrt%2825%29=5 .
That makes 2a=10.
That is the distance between the vertices.

If P is a point in a hyperbola with foci A and B,
abs%28PA-PB%29= distance between the vertices.
So, for this hyperbola
abs%28PA-PB%29=10 ---> %28PA-PB%29%5E2=100

We knew for the ellipse that
PA+PB=50 ---> %28PA%2BPB%29%5E2=2500 .

Since 4PA%2APB=%28PA%2BPB%29%5E2-%28PA-PB%29%5E2 ,
4PA%2APB=2500-100=2400
PA%2APB=2400%2F4 and highlight%28PA%2APB=600%29