Question 1070232: In a circle,OS is prependicular to the chord PQ of a circle whose centre is O.If QR is a diameter,show that QP=2OS
Found 2 solutions by ikleyn, Paras kohli:
Answer by ikleyn(52839)   (Show Source):
You can put this solution on YOUR website! .
This statement is wrong.
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I have read the "solution" by "Paras kohli",
and I can say that not only the statement is wrong, but the "solution" is wrong, too.
After reading his solution, I clearly see the style and the level of its author.
I want to say that we do not need the tutors of such style and level at this forum.
Answer by Paras kohli(1)  (Show Source):
You can put this solution on YOUR website! Ohkay, so imagine a circle, where, P and Q are the end points of a diametre ( so it's in the middle) And if O is in the middle of P and Q(diameter) and finishes with S, that means O and S are the radius (which is just half of the diamtre) Meaning QP (diameter)=2OS(radius)
So:
Diametre= 2x radius
PQ=2OS
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