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Q) The points (8, 4) is on the circle that is tangent to the line 3y-4x-11=0 at (1, 5). Find the equation of the circle. Where does it cut the x-axis?
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Q) The points (8, 4) is on the circle that is tangent to the line 3y-4x-11=0 at (1, 5). Find the equation of the circle. Where does it cut the x-axis?
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Question 1067029: Please help me solve this.
Q) The points (8, 4) is on the circle that is tangent to the line 3y-4x-11=0 at (1, 5). Find the equation of the circle. Where does it cut the x-axis? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! The points A(8,4) is on the circle that is tangent to the line 3y-4x-11=0
at B(1,5). Find the equation of the circle. Where does it cut the x-axis?
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Find the PB (perpendicular bisector) of AB.
The center of the circle is on that line.
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Find the equation of the line perpendicular to the given line thru B.
The center of the circle is on that line.
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Find the intersection of the 2 lines --> center C (h,k).
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The radius r is the distance AC or BC.
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