SOLUTION: For the equation 4x^2+4y^2−32x+16y−20=0 how to find the center and radius

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Question 1066997: For the equation 4x^2+4y^2−32x+16y−20=0 how to find the center and radius
Answer by josgarithmetic(39621) About Me  (Show Source):
You can put this solution on YOUR website!
Complete the squares, if necessary, and put into standard form %28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2.