SOLUTION: The perimeter of a triangle is 44 cm. One of its sides is 4 cm smaller than the other and twice as long as the third side. Find the sides of the triangle?
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Question 1064160: The perimeter of a triangle is 44 cm. One of its sides is 4 cm smaller than the other and twice as long as the third side. Find the sides of the triangle? Found 2 solutions by Alan3354, MathTherapy:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! The perimeter of a triangle is 44 cm. One of its sides is 4 cm smaller than the other and twice as long as the third side. Find the sides of the triangle?
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If by "the other" you mean side 2
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s = side 2
side 1 = s - 4
side 3 = (1/2)s
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s + s-4 + s/2 = 44
2s - 4 + s/2 = 44
4s - 8 + s = 88
5s = 96
s = 19.2
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--> 19.2, 15.2 & 9.6
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It's not a clearly stated problem.
Math problems should not be subject to interpretation.
You can put this solution on YOUR website!
The perimeter of a triangle is 44 cm. One of its sides is 4 cm smaller than the other and twice as long as the third side. Find the sides of the triangle?
Let the other (2nd) side be S
Then 1st side = S - 4
Also, 1st side is twice 3rd side, or 3rd side is
Since the sides sum to 44 cm, we get:
4S + S - 4 = 96 ------- Multiplying by LCD, 2
5S = 96 + 4
5S = 100
S, or
