SOLUTION: Given A(-1,4) and B(3,-2). A find the midpoint of AB. B)Find the equation to the line through A and B. In slope intercept form. C)General form with integer coefficients

Algebra ->  Points-lines-and-rays -> SOLUTION: Given A(-1,4) and B(3,-2). A find the midpoint of AB. B)Find the equation to the line through A and B. In slope intercept form. C)General form with integer coefficients      Log On


   



Question 1063623: Given A(-1,4) and B(3,-2). A find the midpoint of AB.
B)Find the equation to the line through A and B. In slope intercept form.
C)General form with integer coefficients

Answer by sky1983(10) About Me  (Show Source):
You can put this solution on YOUR website!
the midpoint is the average of the two points
x = (-1+3)/2 = 2/2 = 1
y = [4+(-2)]/2 = 2/2 = 1
the midpoint is at (1,1)
to find the equation in slope intercept form, find first the slope
m = [4-(-2)]/[-1-3] = 6/-4 = -3/2
from y = mx + b, solve for b using any of the given points, in here i will use point A(-1,4)
4 =(-3/2)(-1) + b
4 = 3/2 + b
b=5/2
so our equation is,
y = (-3/2)x + 5/2
The "General Form" of the equation of a straight line is:
Ax + By + C = 0
y = (-3/2)x + 5/2
y + (3/2)x - 5/2 = 0
rearrange
(3/2)x + y - 5/2 = 0

cheers mate!
sky1983