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Question 1062207: Find the value of y such that the distance between the points (5,3) and (2,y) is 5 units.
The values of y are ____ and ____
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Find the value of y such that the distance between the points (5,3) and (2,y) is 5 units.
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d = sqrt[(y2-y1)^2 + (x2-x1)^2]
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25 = (y-3)^2 + (2-5)^2
25 = y^2-6y+9 +9
y^2 - 6y -7 = 0
(y-7)(y+1) = 0
The values of y are _7___ and _-1
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Cheers,
Stan H.
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