SOLUTION: In still&#8203; water, a boat averages 18 miles per hour. It takes the same amount of time to travel 16 miles &#8203;downstream, with the&#8203; current, as it does 8 miles&#8203;

Click here to see ALL problems on Rational-functions

Question 1059311: In still water, a boat averages 18 miles per hour. It takes the same amount of
time to travel 16 miles downstream, with the current, as it does 8 miles upstream,
against the current. What is the rate of the water's current?
Found 2 solutions by josgarithmetic, josmiceli:
Answer by josgarithmetic(39630) (Show Source):
You can put this solution on YOUR website!
Your exercise is the same kind of form as another very similar exercise recently solved. What are known and unknown are different between the two but the form is otherwise the same.

Check this one very thoroughly for help:
https://www.algebra.com/algebra/homework/word/misc/Miscellaneous_Word_Problems.faq.question.1059114.html, Travel with and against river current, equal times, but different distances

Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website!
Let = the rate of the current in hrs
Let = the time in hrs to go either
downstream or upstream
--------------------------------------
Going downstream:
(1)
Going upstream:
(2)
-----------------------
(1)
Plug (1) into (2)
------------------------------------
(2)
(2)
(2)
(2)
(2)
-------------------
The rate of the current is 6 mi/hr

SOLUTION: In still&#8203; water, a boat averages 18 miles per hour. It takes the same amount of time to travel 16 miles &#8203;downstream, with the&#8203; current, as it does 8 miles&#8203;

SOLUTION: In still water, a boat averages 18 miles per hour. It takes the same amount of time to travel 16 miles downstream, with the current, as it does 8 miles