SOLUTION: Write the equation of the perpendicular bisector to the line segment with endpoints (-1, -3 ) ( 3, 3 )

Algebra ->  Points-lines-and-rays -> SOLUTION: Write the equation of the perpendicular bisector to the line segment with endpoints (-1, -3 ) ( 3, 3 )      Log On


   

Question 1056266: Write the equation of the perpendicular bisector to the line segment with endpoints (-1, -3 ) ( 3, 3 )
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
( -1, -3 ) and ( 3, 3 )
The x-value of midpoint:
+%28+-1+%2B+3+%29+%2F+2+=+1+
The y-value of midpoint:
+%28+3+-+3+%29+%2F+2+=+0+
-----------------------
The midpoint is at ( 1, 0 )
-----------------------
The slope of this line segment is:
+%28+3+-%28-3%29+%29+%2F+%28+3+-%28-1%29+%29+=+6%2F4+
+6%2F4+=+3%2F2+
------------------------------
Any line perpendicular to this
segment will have slope
+m+=+-1%2F%28+3%2F2%29+
+m+=+-2%2F3+
-------------------------------
Use point-slope formula
+%28+y+-+0+%29+%2F+%28+x+-+1+%29+=+-2%2F3+
+y+=+%28-2%2F3%29%2A%28+x+-+1+%29+
+y+=+-%282%2F3%29%2Ax+%2B+2%2F3+
----------------------------
check:
does it go through ( 1, 0 ) ?
+0+=+-%282%2F3%29%2A1+%2B+2%2F3+
+0+=+0+
OK